mirror of
https://git.teknik.io/Teknikode/Teknik.git
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47 lines
2.1 KiB
Plaintext
47 lines
2.1 KiB
Plaintext
@model LoginWith2faViewModel
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<div class="container">
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<div class="row">
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<div class="col-md-12">
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<div class="row">
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<div class="col-md-8 col-md-offset-2 text-center">
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<h1>Two-factor authentication</h1>
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<hr />
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<p>Your login is protected with an authenticator app. Enter your authenticator code below.</p>
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</div>
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</div>
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<div class="row">
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<div class="col-md-4 col-md-offset-4">
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<form method="post" asp-route-returnUrl="@ViewData["ReturnUrl"]">
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<input asp-for="RememberMe" type="hidden" />
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<div asp-validation-summary="All" class="text-danger"></div>
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<div class="form-group">
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<label asp-for="TwoFactorCode"></label>
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<input asp-for="TwoFactorCode" class="form-control" autocomplete="off" />
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<span asp-validation-for="TwoFactorCode" class="text-danger"></span>
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</div>
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<div class="form-group">
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<div class="abc-checkbox">
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<input asp-for="RememberMachine" />
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<label asp-for="RememberMachine">@Html.DisplayNameFor(m => m.RememberMachine)</label>
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</div>
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</div>
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<div class="form-group pull-right">
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<button type="submit" class="btn btn-default">Log in</button>
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</div>
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</form>
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</div>
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</div>
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<br />
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<div class="row">
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<div class="col-md-8 col-md-offset-2 text-center">
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<p>
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Don't have access to your authenticator device? You can
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<a asp-action="LoginWithRecoveryCode" asp-route-returnUrl="@ViewData["ReturnUrl"]">log in with a recovery code</a>.
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</p>
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</div>
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</div>
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</div>
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</div>
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</div>
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