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[utils] Support ttaf1 namespace in TTML
It's found in bbc.co.uk. See #6038
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@ -1841,7 +1841,10 @@ def srt_subtitles_timecode(seconds):
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def dfxp2srt(dfxp_data):
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_x = functools.partial(xpath_with_ns, ns_map={'ttml': 'http://www.w3.org/ns/ttml'})
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_x = functools.partial(xpath_with_ns, ns_map={
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'ttml': 'http://www.w3.org/ns/ttml',
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'ttaf1': 'http://www.w3.org/2006/10/ttaf1',
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})
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def parse_node(node):
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str_or_empty = functools.partial(str_or_none, default='')
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@ -1849,9 +1852,9 @@ def parse_node(node):
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out = str_or_empty(node.text)
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for child in node:
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if child.tag in (_x('ttml:br'), 'br'):
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if child.tag in (_x('ttml:br'), _x('ttaf1:br'), 'br'):
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out += '\n' + str_or_empty(child.tail)
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elif child.tag in (_x('ttml:span'), 'span'):
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elif child.tag in (_x('ttml:span'), _x('ttaf1:span'), 'span'):
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out += str_or_empty(parse_node(child))
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else:
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out += str_or_empty(xml.etree.ElementTree.tostring(child))
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@ -1860,7 +1863,7 @@ def parse_node(node):
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dfxp = xml.etree.ElementTree.fromstring(dfxp_data.encode('utf-8'))
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out = []
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paras = dfxp.findall(_x('.//ttml:p')) or dfxp.findall('.//p')
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paras = dfxp.findall(_x('.//ttml:p')) or dfxp.findall(_x('.//ttaf1:p')) or dfxp.findall('.//p')
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if not paras:
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raise ValueError('Invalid dfxp/TTML subtitle')
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