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[MCA] [In-order pipeline] Fix for 0 latency instruction causing assertion to fail.
0 latency instructions now get processed and retired properly within the in-order pipeline. Had to fix a bug within TimelineView.cpp as well that would show up when a 0 latency instruction was the first instruction in the source. Differential Revision: https://reviews.llvm.org/D104675
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@ -241,6 +241,18 @@ llvm::Error InOrderIssueStage::tryIssue(InstRef &IR) {
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Bandwidth = Desc.EndGroup ? 0 : Bandwidth - NumMicroOps;
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Bandwidth = Desc.EndGroup ? 0 : Bandwidth - NumMicroOps;
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}
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}
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// If the instruction has a latency of 0, we need to handle
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// the execution and retirement now.
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if (IS.isExecuted()) {
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PRF.onInstructionExecuted(&IS);
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notifyEvent<HWInstructionEvent>(
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HWInstructionEvent(HWInstructionEvent::Executed, IR));
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LLVM_DEBUG(dbgs() << "[E] Instruction #" << IR << " is executed\n");
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retireInstruction(IR);
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return llvm::ErrorSuccess();
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}
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IssuedInst.push_back(IR);
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IssuedInst.push_back(IR);
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if (!IR.getInstruction()->getDesc().RetireOOO)
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if (!IR.getInstruction()->getDesc().RetireOOO)
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@ -288,8 +288,6 @@ void TimelineView::printTimeline(raw_ostream &OS) const {
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for (unsigned Iteration = 0; Iteration < Iterations; ++Iteration) {
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for (unsigned Iteration = 0; Iteration < Iterations; ++Iteration) {
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for (const MCInst &Inst : Source) {
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for (const MCInst &Inst : Source) {
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const TimelineViewEntry &Entry = Timeline[IID];
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const TimelineViewEntry &Entry = Timeline[IID];
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if (Entry.CycleRetired == 0)
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return;
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unsigned SourceIndex = IID % Source.size();
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unsigned SourceIndex = IID % Source.size();
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printTimelineViewEntry(FOS, Entry, Iteration, SourceIndex);
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printTimelineViewEntry(FOS, Entry, Iteration, SourceIndex);
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