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Exploit distributive laws (eg: And distributes over Or, Mul over Add, etc) in a
fairly systematic way in instcombine. Some of these cases were already dealt with, in which case I removed the existing code. The case of Add has a bunch of funky logic which covers some of this plus a few variants (considers shifts to be a form of multiplication), which I didn't touch. The simplification performed is: A*B+A*C -> A*(B+C). The improvement is to do this in cases that were not already handled [such as A*B-A*C -> A*(B-C), which was reported on the mailing list], and also to do it more often by not checking for "only one use" if "B+C" simplifies. llvm-svn: 120024
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@ -290,6 +290,12 @@ private:
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/// operators which are associative or commutative.
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bool SimplifyAssociativeOrCommutative(BinaryOperator &I);
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/// SimplifyDistributed - This tries to simplify binary operations which some
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/// other binary operation distributes over (eg "A*B+A*C" -> "A*(B+C)" since
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/// addition is distributed over by multiplication). Returns the result of
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/// the simplification, or null if no simplification was performed.
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Instruction *SimplifyDistributed(BinaryOperator &I);
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/// SimplifyDemandedUseBits - Attempts to replace V with a simpler value
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/// based on the demanded bits.
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Value *SimplifyDemandedUseBits(Value *V, APInt DemandedMask,
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@ -91,6 +91,8 @@ Instruction *InstCombiner::visitAdd(BinaryOperator &I) {
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I.hasNoUnsignedWrap(), TD))
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return ReplaceInstUsesWith(I, V);
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if (Instruction *NV = SimplifyDistributed(I)) // (A*B)+(A*C) -> A*(B+C)
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return NV;
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if (Constant *RHSC = dyn_cast<Constant>(RHS)) {
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if (ConstantInt *CI = dyn_cast<ConstantInt>(RHSC)) {
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@ -548,6 +550,9 @@ Instruction *InstCombiner::visitSub(BinaryOperator &I) {
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if (Op0 == Op1) // sub X, X -> 0
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return ReplaceInstUsesWith(I, Constant::getNullValue(I.getType()));
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if (Instruction *NV = SimplifyDistributed(I)) // (A*B)-(A*C) -> A*(B-C)
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return NV;
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// If this is a 'B = x-(-A)', change to B = x+A. This preserves NSW/NUW.
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if (Value *V = dyn_castNegVal(Op1)) {
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BinaryOperator *Res = BinaryOperator::CreateAdd(Op0, V);
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@ -984,6 +984,9 @@ Instruction *InstCombiner::visitAnd(BinaryOperator &I) {
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if (Value *V = SimplifyAndInst(Op0, Op1, TD))
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return ReplaceInstUsesWith(I, V);
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if (Instruction *NV = SimplifyDistributed(I)) // (A|B)&(A|C) -> A|(B&C)
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return NV;
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// See if we can simplify any instructions used by the instruction whose sole
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// purpose is to compute bits we don't care about.
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if (SimplifyDemandedInstructionBits(I))
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@ -1692,6 +1695,9 @@ Instruction *InstCombiner::visitOr(BinaryOperator &I) {
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if (Value *V = SimplifyOrInst(Op0, Op1, TD))
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return ReplaceInstUsesWith(I, V);
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if (Instruction *NV = SimplifyDistributed(I)) // (A&B)|(A&C) -> A&(B|C)
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return NV;
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// See if we can simplify any instructions used by the instruction whose sole
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// purpose is to compute bits we don't care about.
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if (SimplifyDemandedInstructionBits(I))
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@ -1766,7 +1772,7 @@ Instruction *InstCombiner::visitOr(BinaryOperator &I) {
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Value *C = 0, *D = 0;
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if (match(Op0, m_And(m_Value(A), m_Value(C))) &&
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match(Op1, m_And(m_Value(B), m_Value(D)))) {
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Value *V1 = 0, *V2 = 0, *V3 = 0;
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Value *V1 = 0, *V2 = 0;
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C1 = dyn_cast<ConstantInt>(C);
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C2 = dyn_cast<ConstantInt>(D);
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if (C1 && C2) { // (A & C1)|(B & C2)
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@ -1824,25 +1830,6 @@ Instruction *InstCombiner::visitOr(BinaryOperator &I) {
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}
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}
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}
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// Check to see if we have any common things being and'ed. If so, find the
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// terms for V1 & (V2|V3).
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if (Op0->hasOneUse() || Op1->hasOneUse()) {
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V1 = 0;
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if (A == B) // (A & C)|(A & D) == A & (C|D)
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V1 = A, V2 = C, V3 = D;
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else if (A == D) // (A & C)|(B & A) == A & (B|C)
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V1 = A, V2 = B, V3 = C;
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else if (C == B) // (A & C)|(C & D) == C & (A|D)
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V1 = C, V2 = A, V3 = D;
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else if (C == D) // (A & C)|(B & C) == C & (A|B)
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V1 = C, V2 = A, V3 = B;
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if (V1) {
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Value *Or = Builder->CreateOr(V2, V3, "tmp");
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return BinaryOperator::CreateAnd(V1, Or);
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}
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}
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// (A & (C0?-1:0)) | (B & ~(C0?-1:0)) -> C0 ? A : B, and commuted variants.
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// Don't do this for vector select idioms, the code generator doesn't handle
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@ -1979,6 +1966,9 @@ Instruction *InstCombiner::visitXor(BinaryOperator &I) {
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if (Value *V = SimplifyXorInst(Op0, Op1, TD))
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return ReplaceInstUsesWith(I, V);
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if (Instruction *NV = SimplifyDistributed(I)) // (A&B)^(A&C) -> A&(B^C)
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return NV;
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// See if we can simplify any instructions used by the instruction whose sole
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// purpose is to compute bits we don't care about.
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if (SimplifyDemandedInstructionBits(I))
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@ -2172,29 +2162,8 @@ Instruction *InstCombiner::visitXor(BinaryOperator &I) {
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if ((A == C && B == D) || (A == D && B == C))
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return BinaryOperator::CreateXor(A, B);
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}
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// (A & B)^(C & D)
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if ((Op0I->hasOneUse() || Op1I->hasOneUse()) &&
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match(Op0I, m_And(m_Value(A), m_Value(B))) &&
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match(Op1I, m_And(m_Value(C), m_Value(D)))) {
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// (X & Y)^(X & Y) -> (Y^Z) & X
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Value *X = 0, *Y = 0, *Z = 0;
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if (A == C)
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X = A, Y = B, Z = D;
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else if (A == D)
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X = A, Y = B, Z = C;
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else if (B == C)
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X = B, Y = A, Z = D;
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else if (B == D)
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X = B, Y = A, Z = C;
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if (X) {
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Value *NewOp = Builder->CreateXor(Y, Z, Op0->getName());
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return BinaryOperator::CreateAnd(NewOp, X);
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}
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}
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}
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// (icmp1 A, B) ^ (icmp2 A, B) --> (icmp3 A, B)
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if (ICmpInst *RHS = dyn_cast<ICmpInst>(I.getOperand(1)))
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if (ICmpInst *LHS = dyn_cast<ICmpInst>(I.getOperand(0)))
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@ -237,6 +237,117 @@ bool InstCombiner::SimplifyAssociativeOrCommutative(BinaryOperator &I) {
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} while (1);
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}
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/// LeftDistributesOverRight - Whether "X LOp (Y ROp Z)" is always equal to
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/// "(X LOp Y) ROp (Z LOp Z)".
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static bool LeftDistributesOverRight(Instruction::BinaryOps LOp,
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Instruction::BinaryOps ROp) {
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switch (LOp) {
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default:
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return false;
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case Instruction::And:
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// And distributes over Or and Xor.
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switch (ROp) {
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default:
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return false;
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case Instruction::Or:
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case Instruction::Xor:
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return true;
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}
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case Instruction::Mul:
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// Multiplication distributes over addition and subtraction.
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switch (ROp) {
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default:
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return false;
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case Instruction::Add:
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case Instruction::Sub:
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return true;
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}
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case Instruction::Or:
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// Or distributes over And.
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switch (ROp) {
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default:
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return false;
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case Instruction::And:
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return true;
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}
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}
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}
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/// RightDistributesOverLeft - Whether "(X LOp Y) ROp Z" is always equal to
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/// "(X ROp Z) LOp (Y ROp Z)".
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static bool RightDistributesOverLeft(Instruction::BinaryOps LOp,
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Instruction::BinaryOps ROp) {
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if (Instruction::isCommutative(ROp))
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return LeftDistributesOverRight(ROp, LOp);
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// TODO: It would be nice to handle division, aka "(X + Y)/Z = X/Z + Y/Z",
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// but this requires knowing that the addition does not overflow and other
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// such subtleties.
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return false;
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}
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/// SimplifyDistributed - This tries to simplify binary operations which some
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/// other binary operation distributes over (eg "A*B+A*C" -> "A*(B+C)" since
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/// addition is distributed over by multiplication). Returns the result of
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/// the simplification, or null if no simplification was performed.
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Instruction *InstCombiner::SimplifyDistributed(BinaryOperator &I) {
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BinaryOperator *Op0 = dyn_cast<BinaryOperator>(I.getOperand(0));
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BinaryOperator *Op1 = dyn_cast<BinaryOperator>(I.getOperand(1));
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if (!Op0 || !Op1 || Op0->getOpcode() != Op1->getOpcode())
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return 0;
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// The instruction has the form "(A op' B) op (C op' D)".
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Value *A = Op0->getOperand(0); Value *B = Op0->getOperand(1);
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Value *C = Op1->getOperand(0); Value *D = Op1->getOperand(1);
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Instruction::BinaryOps OuterOpcode = I.getOpcode(); // op
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Instruction::BinaryOps InnerOpcode = Op0->getOpcode(); // op'
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// Does "X op' (Y op Z)" always equal "(X op' Y) op (X op' Z)"?
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bool LeftDistributes = LeftDistributesOverRight(InnerOpcode, OuterOpcode);
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// Does "(X op Y) op' Z" always equal "(X op' Z) op (Y op' Z)"?
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bool RightDistributes = RightDistributesOverLeft(OuterOpcode, InnerOpcode);
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// Does "X op' Y" always equal "Y op' X"?
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bool InnerCommutative = Instruction::isCommutative(InnerOpcode);
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if (LeftDistributes)
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// Does the instruction have the form "(A op' B) op (A op' D)" or, in the
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// commutative case, "(A op' B) op (C op' A)"?
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if (A == C || (InnerCommutative && A == D)) {
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if (A != C)
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std::swap(C, D);
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// Consider forming "A op' (B op D)".
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// If "B op D" simplifies then it can be formed with no cost.
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Value *RHS = SimplifyBinOp(OuterOpcode, B, D, TD);
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// If "B op D" doesn't simplify then only proceed if both of the existing
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// operations "A op' B" and "C op' D" will be zapped since no longer used.
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if (!RHS && Op0->hasOneUse() && Op1->hasOneUse())
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RHS = Builder->CreateBinOp(OuterOpcode, B, D, Op1->getName());
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if (RHS)
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return BinaryOperator::Create(InnerOpcode, A, RHS);
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}
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if (RightDistributes)
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// Does the instruction have the form "(A op' B) op (C op' B)" or, in the
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// commutative case, "(A op' B) op (B op' D)"?
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if (B == D || (InnerCommutative && B == C)) {
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if (B != D)
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std::swap(C, D);
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// Consider forming "(A op C) op' B".
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// If "A op C" simplifies then it can be formed with no cost.
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Value *LHS = SimplifyBinOp(OuterOpcode, A, C, TD);
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// If "A op C" doesn't simplify then only proceed if both of the existing
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// operations "A op' B" and "C op' D" will be zapped since no longer used.
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if (!LHS && Op0->hasOneUse() && Op1->hasOneUse())
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LHS = Builder->CreateBinOp(OuterOpcode, A, C, Op0->getName());
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if (LHS)
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return BinaryOperator::Create(InnerOpcode, LHS, B);
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}
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return 0;
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}
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// dyn_castNegVal - Given a 'sub' instruction, return the RHS of the instruction
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// if the LHS is a constant zero (which is the 'negate' form).
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//
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11
test/Transforms/InstCombine/2010-11-23-Distributed.ll
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11
test/Transforms/InstCombine/2010-11-23-Distributed.ll
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@ -0,0 +1,11 @@
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; RUN: opt < %s -instcombine -S | FileCheck %s
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define i32 @foo(i32 %x, i32 %y) {
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; CHECK: @foo
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%add = add nsw i32 %y, %x
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%mul = mul nsw i32 %add, %y
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%square = mul nsw i32 %y, %y
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%res = sub i32 %mul, %square
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; CHECK: %res = mul i32 %x, %y
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ret i32 %res
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; CHECK: ret i32 %res
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}
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