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llvm-undname: Improve string literal demangling with embedded \0 chars
- Don't assert when a string looks like a u32 string to the heuristic but doesn't have a length that's 0 mod 4. Instead, classify those as u16 with embedded \0 chars. Found by oss-fuzz. - Print embedded nul bytes as \0 instead of \x00. llvm-svn: 358835
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@ -1088,6 +1088,9 @@ static void outputHex(OutputStream &OS, unsigned C) {
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static void outputEscapedChar(OutputStream &OS, unsigned C) {
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switch (C) {
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case '\0': // nul
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OS << "\\0";
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return;
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case '\'': // single quote
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OS << "\\\'";
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return;
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@ -1165,7 +1168,7 @@ static unsigned guessCharByteSize(const uint8_t *StringBytes, unsigned NumChars,
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// 2-byte, or 4-byte null terminator.
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if (NumBytes < 32) {
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unsigned TrailingNulls = countTrailingNullBytes(StringBytes, NumChars);
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if (TrailingNulls >= 4)
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if (TrailingNulls >= 4 && NumBytes % 4 == 0)
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return 4;
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if (TrailingNulls >= 2)
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return 2;
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@ -1179,7 +1182,7 @@ static unsigned guessCharByteSize(const uint8_t *StringBytes, unsigned NumChars,
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// perfect and is biased towards languages that have ascii alphabets, but this
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// was always going to be best effort since the encoding is lossy.
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unsigned Nulls = countEmbeddedNulls(StringBytes, NumChars);
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if (Nulls >= 2 * NumChars / 3)
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if (Nulls >= 2 * NumChars / 3 && NumBytes % 4 == 0)
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return 4;
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if (Nulls >= NumChars / 3)
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return 2;
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@ -771,3 +771,13 @@
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??_C@_0CG@HJGBPLNO@l?$AAo?$AAo?$AAk?$AAA?$AAh?$AAe?$AAa?$AAd?$AAH?$AAa?$AAr?$AAd?$AAB?$AAr?$AAe?$AA@
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; CHECK: u"lookAheadHardBre"...
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; These are u16 strings that the diagnostic would classify as u32 -- except
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; that their byte length % 4 is 2, so they can't be u32.
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??_C@_05LABPAAN@b?$AA?$AA?$AA?$AA?$AA@
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; CHECK: u"b\0"
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??_C@_0CC@MBPKDIAM@a?$AA?$AA?$AAb?$AA?$AA?$AAc?$AA?$AA?$AAd?$AA?$AA?$AAe?$AA?$AA?$AAf?$AA?$AA?$AAg?$AA?$AA?$AAh?$AA?$AA?$AA@
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; CHECK: u"a\0b\0c\0d\0e\0f\0g\0h\0"...
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