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Use gcc's rules for parsing gcc-style response files
In gcc, \ escapes every character in response files. It is true that this makes it harder to mention Windows files in rsp files, but not doing this means clang disagrees with gcc, and also disagrees with the shell (on non-Windows) which rsp file quoting is supposed to match. clang isn't free to choose what to do here. In general, the idea for response files is to take bits of your command line and write them to a file unchanged, and have things work the same way. Since the command line would've been interpreted by the shell, things in the rsp file need to be subject to the same shell quoting rules. People who want to put Windows-style paths in their response files either need to do any of: * escape their backslashes * or use clang-cl which uses cl.exe/cmd.exe quoting rules * pass --rsp-quoting=windows to clang to tell it to use cl.exe/cmd.exe quoting rules for response files. Fixes PR27464. http://reviews.llvm.org/D19417 llvm-svn: 267556
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@ -515,8 +515,6 @@ static bool isWhitespace(char C) { return strchr(" \t\n\r\f\v", C); }
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static bool isQuote(char C) { return C == '\"' || C == '\''; }
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static bool isGNUSpecial(char C) { return strchr("\\\"\' ", C); }
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void cl::TokenizeGNUCommandLine(StringRef Src, StringSaver &Saver,
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SmallVectorImpl<const char *> &NewArgv,
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bool MarkEOLs) {
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@ -534,9 +532,8 @@ void cl::TokenizeGNUCommandLine(StringRef Src, StringSaver &Saver,
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break;
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}
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// Backslashes can escape backslashes, spaces, and other quotes. Otherwise
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// they are literal. This makes it much easier to read Windows file paths.
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if (I + 1 < E && Src[I] == '\\' && isGNUSpecial(Src[I + 1])) {
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// Backslash escapes the next character.
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if (I + 1 < E && Src[I] == '\\') {
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++I; // Skip the escape.
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Token.push_back(Src[I]);
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continue;
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@ -546,8 +543,8 @@ void cl::TokenizeGNUCommandLine(StringRef Src, StringSaver &Saver,
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if (isQuote(Src[I])) {
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char Quote = Src[I++];
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while (I != E && Src[I] != Quote) {
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// Backslashes are literal, unless they escape a special character.
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if (Src[I] == '\\' && I + 1 != E && isGNUSpecial(Src[I + 1]))
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// Backslash escapes the next character.
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if (Src[I] == '\\' && I + 1 != E)
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++I;
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Token.push_back(Src[I]);
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++I;
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@ -165,11 +165,12 @@ void testCommandLineTokenizer(ParserFunction *parse, const char *Input,
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}
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TEST(CommandLineTest, TokenizeGNUCommandLine) {
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const char *Input = "foo\\ bar \"foo bar\" \'foo bar\' 'foo\\\\bar' "
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"foo\"bar\"baz C:\\src\\foo.cpp \"C:\\src\\foo.cpp\"";
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const char *const Output[] = { "foo bar", "foo bar", "foo bar", "foo\\bar",
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"foobarbaz", "C:\\src\\foo.cpp",
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"C:\\src\\foo.cpp" };
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const char *Input =
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"foo\\ bar \"foo bar\" \'foo bar\' 'foo\\\\bar' -DFOO=bar\\(\\) "
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"foo\"bar\"baz C:\\\\src\\\\foo.cpp \"C:\\src\\foo.cpp\"";
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const char *const Output[] = {
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"foo bar", "foo bar", "foo bar", "foo\\bar",
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"-DFOO=bar()", "foobarbaz", "C:\\src\\foo.cpp", "C:srcfoo.cpp"};
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testCommandLineTokenizer(cl::TokenizeGNUCommandLine, Input, Output,
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array_lengthof(Output));
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}
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