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Don't use std::copy and std::copy_backward, run 10% faster.
Sometimes std::copy can become a memmove call, and that is not a good idea when copying relatively few bytes as we are doing. We also get a small win by changing two loops into one. llvm-svn: 120265
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@ -103,7 +103,6 @@
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#include "llvm/ADT/PointerIntPair.h"
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#include "llvm/Support/Allocator.h"
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#include "llvm/Support/RecyclingAllocator.h"
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#include <limits>
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#include <iterator>
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// FIXME: Remove debugging code.
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@ -211,8 +210,10 @@ public:
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unsigned j, unsigned Count) {
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assert(i + Count <= M && "Invalid source range");
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assert(j + Count <= N && "Invalid dest range");
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std::copy(Other.first + i, Other.first + i + Count, first + j);
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std::copy(Other.second + i, Other.second + i + Count, second + j);
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for (unsigned e = i + Count; i != e; ++i, ++j) {
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first[j] = Other.first[i];
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second[j] = Other.second[i];
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}
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}
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/// moveLeft - Move elements to the left.
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@ -231,8 +232,10 @@ public:
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void moveRight(unsigned i, unsigned j, unsigned Count) {
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assert(i <= j && "Use moveLeft shift elements left");
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assert(j + Count <= N && "Invalid range");
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std::copy_backward(first + i, first + i + Count, first + j + Count);
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std::copy_backward(second + i, second + i + Count, second + j + Count);
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while (Count--) {
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first[j + Count] = first[i + Count];
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second[j + Count] = second[i + Count];
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}
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}
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/// erase - Erase elements [i;j).
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