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New testcases so I don't forget about these algebraic simplifications
llvm-svn: 2479
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31
test/Regression/Transforms/InstCombine/and.ll
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31
test/Regression/Transforms/InstCombine/and.ll
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; This test makes sure that these instructions are properly eliminated.
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;
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; RUN: if as < %s | opt -instcombine -dce | dis | grep and
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; RUN: then exit 1
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; RUN: else exit 0
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; RUN: fi
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implementation
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int "test1"(int %A) {
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%B = and int %A, 0 ; zero result
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ret int %B
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}
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int "test2"(int %A) {
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%B = and int %A, -1 ; noop
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ret int %B
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}
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bool "test3"(bool %A) {
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%B = and bool %A, false ; always = false
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ret bool %B
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}
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bool "test4"(bool %A) {
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%B = and bool %A, true ; noop
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ret bool %B
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}
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41
test/Regression/Transforms/InstCombine/or.ll
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41
test/Regression/Transforms/InstCombine/or.ll
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; This test makes sure that these instructions are properly eliminated.
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;
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; RUN: if as < %s | opt -instcombine -dce | dis | grep or
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; RUN: then exit 1
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; RUN: else exit 0
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; RUN: fi
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implementation
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int "test1"(int %A) {
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%B = or int %A, 0
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ret int %B
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}
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int "test2"(int %A) {
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%B = or int %A, -1
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ret int %B
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}
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bool "test3"(bool %A) {
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%B = or bool %A, false
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ret bool %B
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}
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bool "test4"(bool %A) {
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%B = or bool %A, true
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ret bool %B
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}
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bool "test5"(bool %A) {
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%B = xor bool %A, false
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ret bool %B
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}
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int "test5"(int %A) {
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%B = xor int %A, 0
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ret int %B
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}
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15
test/Regression/Transforms/InstCombine/rem.ll
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15
test/Regression/Transforms/InstCombine/rem.ll
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; This test makes sure that these instructions are properly eliminated.
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;
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; RUN: if as < %s | opt -instcombine -dce | dis | grep rem
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; RUN: then exit 1
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; RUN: else exit 0
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; RUN: fi
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implementation
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int "test1"(int %A) {
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%B = rem int %A, 1 ; ISA constant 0
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ret int %B
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}
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35
test/Regression/Transforms/InstCombine/shift.ll
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35
test/Regression/Transforms/InstCombine/shift.ll
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; This test makes sure that these instructions are properly eliminated.
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;
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; RUN: if as < %s | opt -instcombine -dce | dis | grep sh
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; RUN: then exit 1
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; RUN: else exit 0
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; RUN: fi
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implementation
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int "test1"(int %A) {
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%B = shl int %A, ubyte 0
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ret int %B
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}
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int "test2"(ubyte %A) {
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%B = shl int 0, ubyte %A
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ret int %B
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}
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int "test3"(int %A) {
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%B = shr int %A, ubyte 0
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ret int %B
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}
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int "test4"(ubyte %A) {
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%B = shr int 0, ubyte %A
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ret int %B
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}
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int "test5"(int %A) {
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%B = shr int %A, ubyte 32 ;; shift all bits out
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ret int %B
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}
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