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Handle the case of a no-return invoke correctly. It actually still has

successors, they just are all landing pad successors. We handle this the
same way as no successors. Comments attached for the next person to wade
through here and another lovely test case courtesy of Benjamin Kramer's
bugpoint reduction.

llvm-svn: 145098
This commit is contained in:
Chandler Carruth 2011-11-23 08:23:54 +00:00
parent 8722a53e52
commit c175221b2d
2 changed files with 32 additions and 0 deletions

View File

@ -305,6 +305,14 @@ void MachineBasicBlock::updateTerminator() {
assert(!TBB && "Found more than one non-landing-pad successor!");
TBB = *SI;
}
// If there is no non-landing-pad successor, the block has no
// fall-through edges to be concerned with.
if (!TBB)
return;
// Finally update the unconditional successor to be reached via a branch
// if it would not be reached by fallthrough.
if (!isLayoutSuccessor(TBB))
TII->InsertBranch(*this, TBB, 0, Cond, dl);
}

View File

@ -504,6 +504,30 @@ loop:
br label %loop
}
declare void @fake_throw() noreturn
define void @test_eh_throw() {
; For blocks containing a 'throw' (or similar functionality), we have
; a no-return invoke. In this case, only EH successors will exist, and
; fallthrough simply won't occur. Make sure we don't crash trying to update
; terminators for such constructs.
;
; CHECK: test_eh_throw
; CHECK: %entry
; CHECK: %cleanup
entry:
invoke void @fake_throw() to label %continue unwind label %cleanup
continue:
unreachable
cleanup:
%0 = landingpad { i8*, i32 } personality i8* bitcast (i32 (...)* @__gxx_personality_v0 to i8*)
cleanup
unreachable
}
define void @test_unnatural_cfg_backwards_inner_loop() {
; Test that when we encounter an unnatural CFG structure after having formed
; a chain for an inner loop which happened to be laid out backwards we don't