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[InstCombine] Improve support for ashr in foldICmpAndShift

We can support ashr similar to lshr, if we know that none of the shifted in bits are used. In that case SimplifyDemandedBits would normally convert it to lshr. But that conversion doesn't happen if the shift has additional users.

Differential Revision: https://reviews.llvm.org/D38521

llvm-svn: 314945
This commit is contained in:
Craig Topper 2017-10-04 23:06:13 +00:00
parent 6dee648d90
commit d93296dbb4
2 changed files with 56 additions and 9 deletions

View File

@ -1524,25 +1524,28 @@ Instruction *InstCombiner::foldICmpAndShift(ICmpInst &Cmp, BinaryOperator *And,
const APInt *C3;
if (match(Shift->getOperand(1), m_APInt(C3))) {
bool CanFold = false;
if (ShiftOpcode == Instruction::AShr) {
// There may be some constraints that make this possible, but nothing
// simple has been discovered yet.
CanFold = false;
} else if (ShiftOpcode == Instruction::Shl) {
if (ShiftOpcode == Instruction::Shl) {
// For a left shift, we can fold if the comparison is not signed. We can
// also fold a signed comparison if the mask value and comparison value
// are not negative. These constraints may not be obvious, but we can
// prove that they are correct using an SMT solver.
if (!Cmp.isSigned() || (!C2.isNegative() && !C1.isNegative()))
CanFold = true;
} else if (ShiftOpcode == Instruction::LShr) {
} else {
bool IsAshr = ShiftOpcode == Instruction::AShr;
// For a logical right shift, we can fold if the comparison is not signed.
// We can also fold a signed comparison if the shifted mask value and the
// shifted comparison value are not negative. These constraints may not be
// obvious, but we can prove that they are correct using an SMT solver.
if (!Cmp.isSigned() ||
(!C2.shl(*C3).isNegative() && !C1.shl(*C3).isNegative()))
CanFold = true;
// For an arithmetic shift right we can do the same, if we ensure
// the And doesn't use any bits being shifted in. Normally these would
// be turned into lshr by SimplifyDemandedBits, but not if there is an
// additional user.
if (!IsAshr || (C2.shl(*C3).lshr(*C3) == C2)) {
if (!Cmp.isSigned() ||
(!C2.shl(*C3).isNegative() && !C1.shl(*C3).isNegative()))
CanFold = true;
}
}
if (CanFold) {

View File

@ -1634,6 +1634,50 @@ define i1 @icmp_and_shr_multiuse(i32 %X) {
ret i1 %and3
}
; Variation of the above with an ashr
define i1 @icmp_and_ashr_multiuse(i32 %X) {
; CHECK-LABEL: @icmp_and_ashr_multiuse(
; CHECK-NEXT: [[AND:%.*]] = and i32 [[X:%.*]], 240
; CHECK-NEXT: [[AND2:%.*]] = and i32 [[X]], 496
; CHECK-NEXT: [[TOBOOL:%.*]] = icmp ne i32 [[AND]], 224
; CHECK-NEXT: [[TOBOOL2:%.*]] = icmp ne i32 [[AND2]], 432
; CHECK-NEXT: [[AND3:%.*]] = and i1 [[TOBOOL]], [[TOBOOL2]]
; CHECK-NEXT: ret i1 [[AND3]]
;
%shr = ashr i32 %X, 4
%and = and i32 %shr, 15
%and2 = and i32 %shr, 31 ; second use of the shift
%tobool = icmp ne i32 %and, 14
%tobool2 = icmp ne i32 %and2, 27
%and3 = and i1 %tobool, %tobool2
ret i1 %and3
}
define i1 @icmp_lshr_and_overshift(i8 %X) {
; CHECK-LABEL: @icmp_lshr_and_overshift(
; CHECK-NEXT: [[TOBOOL:%.*]] = icmp ugt i8 [[X:%.*]], 31
; CHECK-NEXT: ret i1 [[TOBOOL]]
;
%shr = lshr i8 %X, 5
%and = and i8 %shr, 15
%tobool = icmp ne i8 %and, 0
ret i1 %tobool
}
; We shouldn't simplify this because the and uses bits that are shifted in.
define i1 @icmp_ashr_and_overshift(i8 %X) {
; CHECK-LABEL: @icmp_ashr_and_overshift(
; CHECK-NEXT: [[SHR:%.*]] = ashr i8 [[X:%.*]], 5
; CHECK-NEXT: [[AND:%.*]] = and i8 [[SHR]], 15
; CHECK-NEXT: [[TOBOOL:%.*]] = icmp ne i8 [[AND]], 0
; CHECK-NEXT: ret i1 [[TOBOOL]]
;
%shr = ashr i8 %X, 5
%and = and i8 %shr, 15
%tobool = icmp ne i8 %and, 0
ret i1 %tobool
}
; PR16244
define i1 @test71(i8* %x) {
; CHECK-LABEL: @test71(