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[X86] Pulled out duplicate mask width calculation. NFCI.

llvm-svn: 268861
This commit is contained in:
Simon Pilgrim 2016-05-07 18:04:24 +00:00
parent d0b4e9facb
commit ecb5f17d8b

View File

@ -24326,6 +24326,7 @@ static bool combineX86ShufflesRecursively(SDValue Op, SDValue Root,
OpMask.size() % RootMask.size() == 0) ||
OpMask.size() == RootMask.size()) &&
"The smaller number of elements must divide the larger.");
int MaskWidth = std::max<int>(OpMask.size(), RootMask.size());
int RootRatio = std::max<int>(1, OpMask.size() / RootMask.size());
int OpRatio = std::max<int>(1, RootMask.size() / OpMask.size());
assert(((RootRatio == 1 && OpRatio == 1) ||
@ -24333,13 +24334,13 @@ static bool combineX86ShufflesRecursively(SDValue Op, SDValue Root,
"Must not have a ratio for both incoming and op masks!");
SmallVector<int, 16> Mask;
Mask.reserve(std::max(OpMask.size(), RootMask.size()));
Mask.reserve(MaskWidth);
// Merge this shuffle operation's mask into our accumulated mask. Note that
// this shuffle's mask will be the first applied to the input, followed by the
// root mask to get us all the way to the root value arrangement. The reason
// for this order is that we are recursing up the operation chain.
for (int i = 0, e = std::max(OpMask.size(), RootMask.size()); i < e; ++i) {
for (int i = 0; i < MaskWidth; ++i) {
int RootIdx = i / RootRatio;
if (RootMask[RootIdx] < 0) {
// This is a zero or undef lane, we're done.