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Only use argv[0] as the main executable name if it exists.

Under some environments, argv[0] doesn't hold a valid file name, but
sys::fs::getMainExecutable will find the main executable properly.

This patch tweaks the logic to fall back to sys::fs::getMainExecutable
in more situations.

Differential Revision: https://reviews.llvm.org/D60730

llvm-svn: 358455
This commit is contained in:
Sean Silva 2019-04-15 22:07:56 +00:00
parent 5bf454216e
commit f94937f3a4

View File

@ -131,8 +131,8 @@ static bool printSymbolizedStackTrace(StringRef Argv0, void **StackTrace,
// If we don't know argv0 or the address of main() at this point, try
// to guess it anyway (it's possible on some platforms).
std::string MainExecutableName =
Argv0.empty() ? sys::fs::getMainExecutable(nullptr, nullptr)
: (std::string)Argv0;
sys::fs::exists(Argv0) ? (std::string)Argv0
: sys::fs::getMainExecutable(nullptr, nullptr);
BumpPtrAllocator Allocator;
StringSaver StrPool(Allocator);
std::vector<const char *> Modules(Depth, nullptr);