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Sanjay Patel 05aab75248 [InstSimplify] fold and/or of fcmp ord/uno when operand is known nnan
The 'ord' and 'uno' predicates have a logic operation for NAN built into their definitions:

FCMP_ORD   =  7,  ///< 0 1 1 1    True if ordered (no nans)
FCMP_UNO   =  8,  ///< 1 0 0 0    True if unordered: isnan(X) | isnan(Y)

So we can simplify patterns like this:

(fcmp ord (known NNAN), X) && (fcmp ord X, Y) --> fcmp ord X, Y
(fcmp uno (known NNAN), X) || (fcmp uno X, Y) --> fcmp uno X, Y

It might be better to split this into (X uno 0) | (Y uno 0) as a canonicalization, but that
would be another patch.

Differential Revision: https://reviews.llvm.org/D40130 

llvm-svn: 318627
2017-11-19 15:34:27 +00:00
2014-03-02 13:08:46 +00:00
2016-01-26 21:29:08 +00:00
2017-09-18 14:33:39 +00:00
2017-01-12 18:02:42 +00:00
2017-08-18 02:39:28 +00:00

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