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Sanjay Patel
05aab75248
[InstSimplify] fold and/or of fcmp ord/uno when operand is known nnan
The 'ord' and 'uno' predicates have a logic operation for NAN built into their definitions: FCMP_ORD = 7, ///< 0 1 1 1 True if ordered (no nans) FCMP_UNO = 8, ///< 1 0 0 0 True if unordered: isnan(X) | isnan(Y) So we can simplify patterns like this: (fcmp ord (known NNAN), X) && (fcmp ord X, Y) --> fcmp ord X, Y (fcmp uno (known NNAN), X) || (fcmp uno X, Y) --> fcmp uno X, Y It might be better to split this into (X uno 0) | (Y uno 0) as a canonicalization, but that would be another patch. Differential Revision: https://reviews.llvm.org/D40130 llvm-svn: 318627
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