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9aba16961d
Causes lld build errors
179 lines
5.0 KiB
C++
179 lines
5.0 KiB
C++
//===-- GlobPattern.cpp - Glob pattern matcher implementation -------------===//
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//
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// Part of the LLVM Project, under the Apache License v2.0 with LLVM Exceptions.
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// See https://llvm.org/LICENSE.txt for license information.
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// SPDX-License-Identifier: Apache-2.0 WITH LLVM-exception
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//
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//===----------------------------------------------------------------------===//
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//
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// This file implements a glob pattern matcher.
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//
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//===----------------------------------------------------------------------===//
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#include "llvm/Support/GlobPattern.h"
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#include "llvm/ADT/ArrayRef.h"
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#include "llvm/ADT/Optional.h"
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#include "llvm/ADT/StringRef.h"
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#include "llvm/Support/Errc.h"
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using namespace llvm;
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static bool hasWildcard(StringRef S) {
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return S.find_first_of("?*[\\") != StringRef::npos;
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}
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// Expands character ranges and returns a bitmap.
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// For example, "a-cf-hz" is expanded to "abcfghz".
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static Expected<BitVector> expand(StringRef S, StringRef Original) {
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BitVector BV(256, false);
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// Expand X-Y.
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for (;;) {
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if (S.size() < 3)
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break;
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uint8_t Start = S[0];
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uint8_t End = S[2];
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// If it doesn't start with something like X-Y,
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// consume the first character and proceed.
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if (S[1] != '-') {
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BV[Start] = true;
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S = S.substr(1);
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continue;
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}
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// It must be in the form of X-Y.
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// Validate it and then interpret the range.
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if (Start > End)
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return make_error<StringError>("invalid glob pattern: " + Original,
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errc::invalid_argument);
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for (int C = Start; C <= End; ++C)
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BV[(uint8_t)C] = true;
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S = S.substr(3);
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}
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for (char C : S)
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BV[(uint8_t)C] = true;
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return BV;
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}
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// This is a scanner for the glob pattern.
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// A glob pattern token is one of "*", "?", "\", "[<chars>]", "[^<chars>]"
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// (which is a negative form of "[<chars>]"), "[!<chars>]" (which is
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// equivalent to "[^<chars>]"), or a non-meta character.
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// This function returns the first token in S.
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static Expected<BitVector> scan(StringRef &S, StringRef Original) {
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switch (S[0]) {
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case '*':
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S = S.substr(1);
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// '*' is represented by an empty bitvector.
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// All other bitvectors are 256-bit long.
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return BitVector();
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case '?':
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S = S.substr(1);
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return BitVector(256, true);
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case '[': {
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// ']' is allowed as the first character of a character class. '[]' is
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// invalid. So, just skip the first character.
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size_t End = S.find(']', 2);
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if (End == StringRef::npos)
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return make_error<StringError>("invalid glob pattern: " + Original,
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errc::invalid_argument);
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StringRef Chars = S.substr(1, End - 1);
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S = S.substr(End + 1);
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if (Chars.startswith("^") || Chars.startswith("!")) {
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Expected<BitVector> BV = expand(Chars.substr(1), Original);
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if (!BV)
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return BV.takeError();
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return BV->flip();
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}
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return expand(Chars, Original);
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}
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case '\\':
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// Eat this character and fall through below to treat it like a non-meta
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// character.
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S = S.substr(1);
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LLVM_FALLTHROUGH;
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default:
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BitVector BV(256, false);
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BV[(uint8_t)S[0]] = true;
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S = S.substr(1);
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return BV;
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}
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}
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Expected<GlobPattern> GlobPattern::create(StringRef S) {
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GlobPattern Pat;
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// S doesn't contain any metacharacter,
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// so the regular string comparison should work.
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if (!hasWildcard(S)) {
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Pat.Exact = S;
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return Pat;
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}
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// S is something like "foo*", and the "* is not escaped. We can use
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// startswith().
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if (S.endswith("*") && !S.endswith("\\*") && !hasWildcard(S.drop_back())) {
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Pat.Prefix = S.drop_back();
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return Pat;
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}
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// S is something like "*foo". We can use endswith().
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if (S.startswith("*") && !hasWildcard(S.drop_front())) {
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Pat.Suffix = S.drop_front();
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return Pat;
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}
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// Otherwise, we need to do real glob pattern matching.
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// Parse the pattern now.
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StringRef Original = S;
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while (!S.empty()) {
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Expected<BitVector> BV = scan(S, Original);
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if (!BV)
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return BV.takeError();
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Pat.Tokens.push_back(*BV);
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}
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return Pat;
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}
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bool GlobPattern::match(StringRef S) const {
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if (Exact)
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return S == *Exact;
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if (Prefix)
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return S.startswith(*Prefix);
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if (Suffix)
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return S.endswith(*Suffix);
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return matchOne(Tokens, S);
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}
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// Runs glob pattern Pats against string S.
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bool GlobPattern::matchOne(ArrayRef<BitVector> Pats, StringRef S) const {
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for (;;) {
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if (Pats.empty())
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return S.empty();
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// If Pats[0] is '*', try to match Pats[1..] against all possible
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// tail strings of S to see at least one pattern succeeds.
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if (Pats[0].size() == 0) {
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Pats = Pats.slice(1);
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if (Pats.empty())
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// Fast path. If a pattern is '*', it matches anything.
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return true;
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for (size_t I = 0, E = S.size(); I < E; ++I)
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if (matchOne(Pats, S.substr(I)))
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return true;
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return false;
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}
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// If Pats[0] is not '*', it must consume one character.
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if (S.empty() || !Pats[0][(uint8_t)S[0]])
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return false;
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Pats = Pats.slice(1);
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S = S.substr(1);
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}
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}
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