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These splices are interesting because they involve swapping two nodes in the same list. There are two ways to do this. Assuming: A -> B -> [Sentinel] You can either: - splice B before A, with: L.splice(A, L, B) or - splice A before Sentinel, with: L.splice(L.end(), L, A) to create: B -> A -> [Sentinel] These two swapping-splices are somewhat interesting corner cases for maintaining the list invariants. The tests pass even with my new ilist implementation, but I had some doubts about the latter when I was looking at weird UB effects. Since I can't find equivalent explicit test coverage elsewhere it seems prudent to commit. llvm-svn: 278887 |
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