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afbef8f004
Fixes https://bugs.llvm.org/show_bug.cgi?id=39926. The size of the first copy was computed as std::abs(std::abs(LdDisp2) - std::abs(LdDisp1)), which results in skipped bytes if the signs of LdDisp2 and LdDisp1 differ. As far as I can see, this should just be LdDisp2 - LdDisp1. The case where LdDisp1 > LdDisp2 is already handled in the code above, in which case LdDisp2 is set to LdDisp1 and this subtraction will evaluate to Size1 = 0, which is the correct value to skip an overlapping copy. Differential Revision: https://reviews.llvm.org/D55485 llvm-svn: 348750 |
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