We have two sources of known bits:
1. For adds leading ones of either operand are preserved. For sub
leading zeros of LHS and leading ones of RHS become leading zeros in
the result.
2. The saturating math is a select between add/sub and an all-ones/
zero value. As such we can carry out the add/sub known bits
calculation, and only preseve the known one/zero bits respectively.
Differential Revision: https://reviews.llvm.org/D58329
llvm-svn: 355223