gcc-papermario/config/h8300/lib1funcs.asm
2020-09-20 21:06:00 -04:00

782 lines
13 KiB
NASM

;; libgcc1 routines for the Hitachi h8/300 cpu.
;; Contributed by Steve Chamberlain.
;; sac@cygnus.com
/* Copyright (C) 1994 Free Software Foundation, Inc.
This file is free software; you can redistribute it and/or modify it
under the terms of the GNU General Public License as published by the
Free Software Foundation; either version 2, or (at your option) any
later version.
In addition to the permissions in the GNU General Public License, the
Free Software Foundation gives you unlimited permission to link the
compiled version of this file with other programs, and to distribute
those programs without any restriction coming from the use of this
file. (The General Public License restrictions do apply in other
respects; for example, they cover modification of the file, and
distribution when not linked into another program.)
This file is distributed in the hope that it will be useful, but
WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
General Public License for more details.
You should have received a copy of the GNU General Public License
along with this program; see the file COPYING. If not, write to
the Free Software Foundation, 59 Temple Place - Suite 330,
Boston, MA 02111-1307, USA. */
/* As a special exception, if you link this library with other files,
some of which are compiled with GCC, to produce an executable,
this library does not by itself cause the resulting executable
to be covered by the GNU General Public License.
This exception does not however invalidate any other reasons why
the executable file might be covered by the GNU General Public License. */
/* Assembler register definitions. */
#define A0 r0
#define A0L r0l
#define A0H r0h
#define A1 r1
#define A1L r1l
#define A1H r1h
#define A2 r2
#define A2L r2l
#define A2H r2h
#define A3 r3
#define A3L r3l
#define A3H r3h
#define S0 r4
#define S0L r4l
#define S0H r4h
#define S1 r5
#define S1L r5l
#define S1H r5h
#define S2 r6
#define S2L r6l
#define S2H r6h
#ifdef __H8300__
#define MOVP mov.w /* pointers are 16 bits */
#define ADDP add.w
#define CMPP cmp.w
#define PUSHP push
#define POPP pop
#define A0P r0
#define A1P r1
#define A2P r2
#define A3P r3
#define S0P r4
#define S1P r5
#define S2P r6
#endif
#if defined (__H8300H__) || defined (__H8300S__)
#define MOVP mov.l /* pointers are 32 bits */
#define ADDP add.l
#define CMPP cmp.l
#define PUSHP push.l
#define POPP pop.l
#define A0P er0
#define A1P er1
#define A2P er2
#define A3P er3
#define S0P er4
#define S1P er5
#define S2P er6
#define A0E e0
#define A1E e1
#define A2E e2
#define A3E e3
#endif
#ifdef L_cmpsi2
#ifdef __H8300__
.section .text
.align 2
.global ___cmpsi2
___cmpsi2:
cmp.w A2,A0
bne .L2
cmp.w A3,A1
bne .L2
mov.w #1,A0
rts
.L2:
cmp.w A0,A2
bgt .L4
bne .L3
cmp.w A1,A3
bls .L3
.L4:
sub.w A0,A0
rts
.L3:
mov.w #2,A0
.L5:
rts
.end
#endif
#endif /* L_cmpsi2 */
#ifdef L_ucmpsi2
#ifdef __H8300__
.section .text
.align 2
.global ___ucmpsi2
___ucmpsi2:
cmp.w A2,A0
bne .L2
cmp.w A3,A1
bne .L2
mov.w #1,A0
rts
.L2:
cmp.w A0,A2
bhi .L4
bne .L3
cmp.w A1,A3
bls .L3
.L4:
sub.w A0,A0
rts
.L3:
mov.w #2,A0
.L5:
rts
.end
#endif
#endif /* L_ucmpsi2 */
#ifdef L_divhi3
;; HImode divides for the H8/300.
;; We bunch all of this into one object file since there are several
;; "supporting routines".
; general purpose normalize routine
;
; divisor in A0
; dividend in A1
; turns both into +ve numbers, and leaves what the answer sign
; should be in A2L
#ifdef __H8300__
.section .text
.align 2
divnorm:
mov.b #0x0,A2L
or A0H,A0H ; is divisor > 0
bge _lab1
not A0H ; no - then make it +ve
not A0L
adds #1,A0
xor #0x1,A2L ; and remember that in A2L
_lab1: or A1H,A1H ; look at dividend
bge _lab2
not A1H ; it is -ve, make it positive
not A1L
adds #1,A1
xor #0x1,A2L; and toggle sign of result
_lab2: rts
;; Basically the same, except that the sign of the divisor determines
;; the sign.
modnorm:
mov.b #0x0,A2L
or A0H,A0H ; is divisor > 0
bge _lab7
not A0H ; no - then make it +ve
not A0L
adds #1,A0
xor #0x1,A2L ; and remember that in A2L
_lab7: or A1H,A1H ; look at dividend
bge _lab8
not A1H ; it is -ve, make it positive
not A1L
adds #1,A1
_lab8: rts
; A0=A0/A1 signed
.global ___divhi3
___divhi3:
bsr divnorm
bsr ___udivhi3
negans: or A2L,A2L ; should answer be negative ?
beq _lab4
not A0H ; yes, so make it so
not A0L
adds #1,A0
_lab4: rts
; A0=A0%A1 signed
.global ___modhi3
___modhi3:
bsr modnorm
bsr ___udivhi3
mov A3,A0
bra negans
; A0=A0%A1 unsigned
.global ___umodhi3
___umodhi3:
bsr ___udivhi3
mov A3,A0
rts
; A0=A0/A1 unsigned
; A3=A0%A1 unsigned
; A2H trashed
; D high 8 bits of denom
; d low 8 bits of denom
; N high 8 bits of num
; n low 8 bits of num
; M high 8 bits of mod
; m low 8 bits of mod
; Q high 8 bits of quot
; q low 8 bits of quot
; P preserve
; The h8 only has a 16/8 bit divide, so we look at the incoming and
; see how to partition up the expression.
.global ___udivhi3
___udivhi3:
; A0 A1 A2 A3
; Nn Dd P
sub.w A3,A3 ; Nn Dd xP 00
or A1H,A1H
bne divlongway
or A0H,A0H
beq _lab6
; we know that D == 0 and N is != 0
mov.b A0H,A3L ; Nn Dd xP 0N
divxu A1L,A3 ; MQ
mov.b A3L,A0H ; Q
; dealt with N, do n
_lab6: mov.b A0L,A3L ; n
divxu A1L,A3 ; mq
mov.b A3L,A0L ; Qq
mov.b A3H,A3L ; m
mov.b #0x0,A3H ; Qq 0m
rts
; D != 0 - which means the denominator is
; loop around to get the result.
divlongway:
mov.b A0H,A3L ; Nn Dd xP 0N
mov.b #0x0,A0H ; high byte of answer has to be zero
mov.b #0x8,A2H ; 8
div8: add.b A0L,A0L ; n*=2
rotxl A3L ; Make remainder bigger
rotxl A3H
sub.w A1,A3 ; Q-=N
bhs setbit ; set a bit ?
add.w A1,A3 ; no : too far , Q+=N
dec A2H
bne div8 ; next bit
rts
setbit: inc A0L ; do insert bit
dec A2H
bne div8 ; next bit
rts
#endif /* __H8300__ */
#endif /* L_divhi3 */
#ifdef L_divsi3
;; 4 byte integer divides for the H8/300.
;;
;; We have one routine which does all the work and lots of
;; little ones which prepare the args and massage the sign.
;; We bunch all of this into one object file since there are several
;; "supporting routines".
#ifdef __H8300H__
.h8300h
#endif
#ifdef __H8300S__
.h8300s
#endif
.section .text
.align 2
; Put abs SIs into r0/r1 and r2/r3, and leave a 1 in r6l with sign of rest.
; This function is here to keep branch displacements small.
#ifdef __H8300__
divnorm:
mov.b #0,S2L ; keep the sign in S2
mov.b A0H,A0H ; is the numerator -ve
bge postive
; negate arg
not A0H
not A1H
not A0L
not A1L
add #1,A1L
addx #0,A1H
addx #0,A0L
addx #0,A0H
mov.b #1,S2L ; the sign will be -ve
postive:
mov.b A2H,A2H ; is the denominator -ve
bge postive2
not A2L
not A2H
not A3L
not A3H
add.b #1,A3L
addx #0,A3H
addx #0,A2L
addx #0,A2H
xor #1,S2L ; toggle result sign
postive2:
rts
;; Basically the same, except that the sign of the divisor determines
;; the sign.
modnorm:
mov.b #0,S2L ; keep the sign in S2
mov.b A0H,A0H ; is the numerator -ve
bge mpostive
; negate arg
not A0H
not A1H
not A0L
not A1L
add #1,A1L
addx #0,A1H
addx #0,A0L
addx #0,A0H
mov.b #1,S2L ; the sign will be -ve
mpostive:
mov.b A2H,A2H ; is the denominator -ve
bge mpostive2
not A2L
not A2H
not A3L
not A3H
add.b #1,A3L
addx #0,A3H
addx #0,A2L
addx #0,A2H
mpostive2:
rts
#else /* __H8300H__ */
divnorm:
mov.b #0,S2L ; keep the sign in S2
mov.l A0P,A0P ; is the numerator -ve
bge postive
neg.l A0P ; negate arg
mov.b #1,S2L ; the sign will be -ve
postive:
mov.l A1P,A1P ; is the denominator -ve
bge postive2
neg.l A1P ; negate arg
xor.b #1,S2L ; toggle result sign
postive2:
rts
;; Basically the same, except that the sign of the divisor determines
;; the sign.
modnorm:
mov.b #0,S2L ; keep the sign in S2
mov.l A0P,A0P ; is the numerator -ve
bge mpostive
neg.l A0P ; negate arg
mov.b #1,S2L ; the sign will be -ve
mpostive:
mov.l A1P,A1P ; is the denominator -ve
bge mpostive2
neg.l A1P ; negate arg
mpostive2:
rts
#endif
; numerator in A0/A1
; denominator in A2/A3
.global ___modsi3
___modsi3:
PUSHP S2P
PUSHP S0P
PUSHP S1P
bsr modnorm
bsr divmodsi4
#ifdef __H8300__
mov S0,A0
mov S1,A1
#else
mov.l S0P,A0P
#endif
bra exitdiv
.global ___udivsi3
___udivsi3:
PUSHP S2P
PUSHP S0P
PUSHP S1P
mov.b #0,S2L ; keep sign low
bsr divmodsi4
bra exitdiv
.global ___umodsi3
___umodsi3:
PUSHP S2P
PUSHP S0P
PUSHP S1P
mov.b #0,S2L ; keep sign low
bsr divmodsi4
#ifdef __H8300__
mov S0,A0
mov S1,A1
#else
mov.l S0P,A0P
#endif
bra exitdiv
.global ___divsi3
___divsi3:
PUSHP S2P
PUSHP S0P
PUSHP S1P
jsr divnorm
jsr divmodsi4
; examine what the sign should be
exitdiv:
POPP S1P
POPP S0P
or S2L,S2L
beq reti
; should be -ve
#ifdef __H8300__
not A0H
not A1H
not A0L
not A1L
add #1,A1L
addx #0,A1H
addx #0,A0L
addx #0,A0H
#else /* __H8300H__ */
neg.l A0P
#endif
reti:
POPP S2P
rts
; takes A0/A1 numerator (A0P for 300h)
; A2/A3 denominator (A1P for 300h)
; returns A0/A1 quotient (A0P for 300h)
; S0/S1 remainder (S0P for 300h)
; trashes S2
#ifdef __H8300__
divmodsi4:
sub.w S0,S0 ; zero play area
mov.w S0,S1
mov.b A2H,S2H
or A2L,S2H
or A3H,S2H
bne DenHighZero
mov.b A0H,A0H
bne NumByte0Zero
mov.b A0L,A0L
bne NumByte1Zero
mov.b A1H,A1H
bne NumByte2Zero
bra NumByte3Zero
NumByte0Zero:
mov.b A0H,S1L
divxu A3L,S1
mov.b S1L,A0H
NumByte1Zero:
mov.b A0L,S1L
divxu A3L,S1
mov.b S1L,A0L
NumByte2Zero:
mov.b A1H,S1L
divxu A3L,S1
mov.b S1L,A1H
NumByte3Zero:
mov.b A1L,S1L
divxu A3L,S1
mov.b S1L,A1L
mov.b S1H,S1L
mov.b #0x0,S1H
rts
; have to do the divide by shift and test
DenHighZero:
mov.b A0H,S1L
mov.b A0L,A0H
mov.b A1H,A0L
mov.b A1L,A1H
mov.b #0,A1L
mov.b #24,S2H ; only do 24 iterations
nextbit:
add.w A1,A1 ; double the answer guess
rotxl A0L
rotxl A0H
rotxl S1L ; double remainder
rotxl S1H
rotxl S0L
rotxl S0H
sub.w A3,S1 ; does it all fit
subx A2L,S0L
subx A2H,S0H
bhs setone
add.w A3,S1 ; no, restore mistake
addx A2L,S0L
addx A2H,S0H
dec S2H
bne nextbit
rts
setone:
inc A1L
dec S2H
bne nextbit
rts
#else /* __H8300H__ */
divmodsi4:
sub.l S0P,S0P ; zero play area
mov.w A1E,A1E ; denominator top word 0?
bne DenHighZero
; do it the easy way, see page 107 in manual
mov.w A0E,A2
extu.l A2P
divxu.w A1,A2P
mov.w A2E,A0E
divxu.w A1,A0P
mov.w A0E,S0
mov.w A2,A0E
extu.l S0P
rts
DenHighZero:
mov.w A0E,A2
mov.b A2H,S0L
mov.b A2L,A2H
mov.b A0H,A2L
mov.w A2,A0E
mov.b A0L,A0H
mov.b #0,A0L
mov.b #24,S2H ; only do 24 iterations
nextbit:
shll.l A0P ; double the answer guess
rotxl.l S0P ; double remainder
sub.l A1P,S0P ; does it all fit?
bhs setone
add.l A1P,S0P ; no, restore mistake
dec S2H
bne nextbit
rts
setone:
inc A0L
dec S2H
bne nextbit
rts
#endif
#endif /* L_divsi3 */
#ifdef L_mulhi3
;; HImode multiply.
; The h8 only has an 8*8->16 multiply.
; The answer is the same as:
;
; product = (srca.l * srcb.l) + ((srca.h * srcb.l) + (srcb.h * srca.l)) * 256
; (we can ignore A1.h * A0.h cause that will all off the top)
; A0 in
; A1 in
; A0 answer
#ifdef __H8300__
.section .text
.align 2
.global ___mulhi3
___mulhi3:
mov.b A1L,A2L ; A2l gets srcb.l
mulxu A0L,A2 ; A2 gets first sub product
mov.b A0H,A3L ; prepare for
mulxu A1L,A3 ; second sub product
add.b A3L,A2H ; sum first two terms
mov.b A1H,A3L ; third sub product
mulxu A0L,A3
add.b A3L,A2H ; almost there
mov.w A2,A0 ; that is
rts
#endif
#endif /* L_mulhi3 */
#ifdef L_mulsi3
;; SImode multiply.
;;
;; I think that shift and add may be sufficient for this. Using the
;; supplied 8x8->16 would need 10 ops of 14 cycles each + overhead. This way
;; the inner loop uses maybe 20 cycles + overhead, but terminates
;; quickly on small args.
;;
;; A0/A1 src_a
;; A2/A3 src_b
;;
;; while (a)
;; {
;; if (a & 1)
;; r += b;
;; a >>= 1;
;; b <<= 1;
;; }
.section .text
.align 2
#ifdef __H8300__
.global ___mulsi3
___mulsi3:
PUSHP S0P
PUSHP S1P
PUSHP S2P
sub.w S0,S0
sub.w S1,S1
; while (a)
_top: mov.w A0,A0
bne _more
mov.w A1,A1
beq _done
_more: ; if (a & 1)
bld #0,A1L
bcc _nobit
; r += b
add.w A3,S1
addx A2L,S0L
addx A2H,S0H
_nobit:
; a >>= 1
shlr A0H
rotxr A0L
rotxr A1H
rotxr A1L
; b <<= 1
add.w A3,A3
addx A2L,A2L
addx A2H,A2H
bra _top
_done:
mov.w S0,A0
mov.w S1,A1
POPP S2P
POPP S1P
POPP S0P
rts
#else /* __H8300H__ */
#ifdef __H8300H__
.h8300h
#endif
#ifdef __H8300S__
.h8300s
#endif
.global ___mulsi3
___mulsi3:
sub.l A2P,A2P
; while (a)
_top: mov.l A0P,A0P
beq _done
; if (a & 1)
bld #0,A0L
bcc _nobit
; r += b
add.l A1P,A2P
_nobit:
; a >>= 1
shlr.l A0P
; b <<= 1
shll.l A1P
bra _top
_done:
mov.l A2P,A0P
rts
#endif
#endif /* L_mulsi3 */